Iris L. answered 05/26/19
Statistician with 20+ experiences with MS Degree in Statistics
I would think the problem as follows (this is for one letter come out):
step one: you fix on a specific letter come out, say, A. then, the total number of combinations containing A would be the number of combinations of randomly selecting 2 letters out of the other six letters, which is 15.
step two: the total number of combination of three letters being randomly selected is 3 out of 7, which is 35.
so, the probability of a specific letter come out is equal to 15/35=0.4286.
Michael S.
So what how would you solve it if you had 6 letters at the beginning, and could fix two letters (say A and G)? Could you please wrote the formulas for this second scenario so that I could understand better?05/26/19