The question doesn't seem to be completely written out here, but I'm guessing that you have to figure out the length and width of the rectangle.
Let's first write out the formula for the perimeter of a rectangle:
P = 2L + 2W
where P = perimeter, L = length, and W = width.
The problem tells us that the rectangle's length is 70 meters longer than its width. OK, it doesn't say meters, but it doesn't say any other unit of measurement, either, so I'm going with it. :)
So:
L = W + 70
Well, if L = W + 70, we can substitute that into our formula for calculating perimeter.
P = 2(W+70) + 2W
P = 2W + 140 + 2W
P = 4W + 140
We know the perimeter is 500 meters (we're told that in the problem). So:
500 = 4W + 140
360 = 4W
90 = W
So the width of the rectangle is 90 meters.
Since the length is equal to the width plus 70, the length must be 160 meters (90 + 70 = 160).
Let's see if we are right:
P = 2L + 2W
500 = 2(160) + 2(90)
500 = 320 + 180 That is true, so we must have the right answers!
