
Patrick B. answered 05/11/19
Math and computer tutor/teacher
g_inverse(-5) = 2 since g(20 = -5
h_inverse(x) = (x-13)/3
h ( h_inverse(-5)) = h ( (5-13)/3 ) = h ( -8/3) = 3(-8/3) + 13 = -8 + 13 = 5
Andrew N.
asked 05/11/19The one-to-one functions g and h are defined as follows. g= {(-5,-3),(0,6),(2,-5),(3,-9)} h(x) = 3x +13 Find the following.
g^-1(-5) =
h^-1(x)+
(h o h ^-1)(-5)=
Patrick B. answered 05/11/19
Math and computer tutor/teacher
g_inverse(-5) = 2 since g(20 = -5
h_inverse(x) = (x-13)/3
h ( h_inverse(-5)) = h ( (5-13)/3 ) = h ( -8/3) = 3(-8/3) + 13 = -8 + 13 = 5
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