Lawrence A. answered 05/06/19
Patient and experienced tutor
Let s = the number of standard downloads.
Let h = the number of high-quality downloads.
The total number of downloads is 1110, therefore
s + h = 1110
That is,
s = 1110 - h (1)
The total megabytes downloaded is 3894. Therefore
2.6s + 4.7h = 3894 (2)
Substitute (1) into (2).
2.6(1110 - h) + 4.7h = 3894
2886 - 2.6h + 4.7h = 3894
2.1h = 3894 - 2886 = 1008
h = 1008/2.1 = 480
From (1), obtain
s = 1110 - 480 = 630
Answer:
480 high-quality downloads.