Equations and substitution

Question

for each of the following equations, show that the given value of x is a solution of the equation by direct substitution.

a) x=4/3 equation: 3x²+5x-12=0

b)x=1+ 6 squared equation: x²-2x-5=0

c)x=1+2i Equation: x²_-2x+5=0

Answer 1

a) 3*(4/3)²+5(4/3)-12 = 16/3 + 20/3 - 12 = 36/3 - 12 = 12 - 12 = 0. So SOLUTION