Matthew C. answered • 05/12/19

UC Berkeley College of Chemistry Grad for Math and Science Tutoring

To answer this, we must first determine Mr. Anderson's speed during the 2 1/4 hrs he drove. We know he drove 5 mi/hr faster than in his previous rate in his first 3 1/2 hrs of driving. Because he drove 168 miles during those 3 1/2 hrs, his average rate of driving must have been:

168 mi/3.5 hrs = 48 mi/hr

Thus, for the next 2 1/4 hrs, Mr. Anderson was driving at a rate of 53 mi/hr. With this, we can now determine how many miles he drove during that time:

53 mi/hr * 2.25 hr = 119.25 miles

Thus, the total distance Mr. Anderson drove was:

168 mi + 119.25 mi = **287.25 mi**