
Matthew C. answered 05/12/19
Master's in Chemistry
To answer this, we must first determine Mr. Anderson's speed during the 2 1/4 hrs he drove. We know he drove 5 mi/hr faster than in his previous rate in his first 3 1/2 hrs of driving. Because he drove 168 miles during those 3 1/2 hrs, his average rate of driving must have been:
168 mi/3.5 hrs = 48 mi/hr
Thus, for the next 2 1/4 hrs, Mr. Anderson was driving at a rate of 53 mi/hr. With this, we can now determine how many miles he drove during that time:
53 mi/hr * 2.25 hr = 119.25 miles
Thus, the total distance Mr. Anderson drove was:
168 mi + 119.25 mi = 287.25 mi