
Robert D. answered 04/11/19
Math/MATLAB/Electrical Engineering Tutor
f(x1)=y (x) = x^2 + 3x +1 (1)
so
f(x2)=y (x+1) = (x+1)^2 + 3(x+1) +1=x^2+5x+5 (2)
(2)-(1)=2x+4
Demi P.
asked 04/11/19The average slope formula is: [f(x2) - f(x1)] / [x2 - x1]
It tells us the average slope over the interval from x1 to x2.
Take the average slope of the function y (x) = x^2 + 3x +1 over one unit intervals from 0 to 5.
Graph the numbers (slopes), and what type of function do you see?
Now repeat the process for g(x) = x^3.
If you are not sure what type of function is gotten here, take the slope of the slope and graph that for a hint.
HOW DO I GRAPH THIS
Robert D. answered 04/11/19
Math/MATLAB/Electrical Engineering Tutor
f(x1)=y (x) = x^2 + 3x +1 (1)
so
f(x2)=y (x+1) = (x+1)^2 + 3(x+1) +1=x^2+5x+5 (2)
(2)-(1)=2x+4
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