Find the mean and standard deviation for the number of orange candies in such groups of 150.

Question

Find the mean and standard deviation for the number of orange candies in such groups of 150.

A random sample of 150 candies contains 44 orange candies. Is this result of unusual? Does it seem that the claimed rate of 18% is wrong?

Find the mean and standard deviation for the number of orange candies in such groups of 150.

A random sample of 150 candies contains 44 orange candies. Is this result of unusual? Does it seem that the claimed rate of 18% is wrong?

Answer 1

44/150=11/30 = (36 2/3)/100 = 36 2/3% not 18%, not close

mean = 36.666...

if standard deviation is less than 9.333.. than 18% is not within a 10% margin of error