This is a Conditional Probability problem
If 4 out of 7 students play soccer
Then 3 out of 7 do not play soccer
The probability of choosing the first non-soccer player will be 3/7
That takes one away from those non-soccer players leaving 2 and it takes 1 away from the total students leaving 6 so the probability of choosing another non-soccer player will be 2/6
That takes one from the non-soccer players leaving 1 and takes a student away from the 6 leaving 5 so the last probability of choosing a non-soccer player is 1/5
Now you multiply the three probabilities together to get the final probability
(3/7)(2/6)(1/5)=6/210
Dividing 6 by 210 yields .0285714
Multiply by 100 to get a percent
2.9%