
Bill K. answered 04/03/19
College professor for working with ADHD/LD
The teacher's first choice has a 2/10 chance of being successful. Now there are only 9 students and only 1 who forgot their lunch, so the chance of picking that person is 1/9. The chance of both choices being successful (the problem states the teacher must get both right) is 2/10 times 1/9, which equals 1/45.