Find the perimeter and the area of a rectangle with the vertices at coordinates (5,3),(5,-2),(-3,-2) and (-3,3)
In order to solve this problem you need to find the distances between the vertices. By inspection the points (5,3) and (5,-2) form one the of the rectangle w = √ ( 5-5)2 + ( -2-3)2 = 5
The length can be obtained by finding distance between the points (5,3) and ( -3,3),
L = √(3-3)2+(-3-5)2 = 8
The perimeter of the rectangle is: P = 2( w + L) = 2 ( 8+5) = 26 units
The area of the rectangle is A = L w, A = 8 x 5 = 40 units2
