Tavares drew a rectangle...the area is 48 square centimetres and its length is 8 centimeters more than its width...lable tje rectangle to tell its length and width

Question

Tavares drew a rectangle...the rectangle area is 48 square centimeters and its length is 8 centimeters more than its width...label the rectangle to twll its length and width

Answer 1

Let w= width, then length= w+8.

Area = lenghth x width

48= w(w+8)

48=w^2+8w

w^2+8w-48=0

(w+12)(w-4)=0.

There are 2 solutions w+12=0 and w-4=0. So w=-12 (discard since cant have a negative width) and w=4 which is the correct answer