J.R. S. answered 03/20/19
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
3 moles CO2 x 44 g/mole = 132 g CO2
132 g/500,000 L x 1000 mg/g = 0.264 mg/liter = 0.264 ppm
Dancin D.
asked 03/19/19If that amount, from problem 7 (the amount is the propane balanced equation: C3H8 + 5O2 = 3CO2 + 4H2O).
J.R. S. answered 03/20/19
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
3 moles CO2 x 44 g/mole = 132 g CO2
132 g/500,000 L x 1000 mg/g = 0.264 mg/liter = 0.264 ppm
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