Zach flies a plane against a headwind for 2816 miles. The return trip with the wind took 20 hours less time. If the wind speed is 10 mph, how fast does Zach fly the plane when there is no wind?

Answer 1

Let the speed at which Zach flies with NO wind be p m/hr.

Then [(2816)/(p-10)] is the time taken flying Against the headwind.

Also [(2816)/(p+10)] is the time taken flying Along the wind.

We then setup the equation [(2816)/(p-10)] =20 + [(2816)/(p+10)]

Solving p = 54m/hr.

Hope this helps and all the best.

Pradip