GRE - Pobability Question?

Question

One person is to be selected at random from a group of 25 people. The probability that the selected person will be a male is 0.44, and the probability that the selected person will be a male who was born before 1960 is 0.28. Quantity A = The number of males in the group who were born in 1960 or later Quantity B = 4 A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. The answer is C. How? I understand that there are 11 males(.44*25) How to find out how many males are there born before 1960?

Answer 1

N= 25

P(male) = 0.44 so 25 x 0.44 = 11 males

therefore, P(female) = 25 - 11 = 14 (assuming only male/female genders, 100% - 44%=56% and 0.56 x 25 =14. Out of 25 people, 11 are males and 14 are females. Together, they make up 100% of 25 people.

P(male and born before 1960) = 0.28 so 25 x 0.28 = 7

therefore, P(male and born in or after 1960) = 11 - 7 = 4. Out of 11 males, 7 are born before 1960 and 4 are born in or after 1960. Together, they make up 100% of all males.

Please note that the problem does not state that of all males, 28% are born before 1960, which would be 11 x 0.28. The probability P(male and born before 1960) is out of 25 people. Another way to say this is: P(male and born before 1960) = P(male) and P(born before 1960) =

0.44 x P(born before 1960) = 0.28.

Answer 2

.44*25 implies that there are 11 males.

.28*25 implies that there are 7 males born before 1960, which hence implies that 4 males were born in 1960 or after.

Therefore, A is equal to B in this case, and the answer is C.