Hello Cazahlaya,
The volume of a cylinder is V = πr2h.
So if you multiply h by 1/3, you get
V = πr2[(1/3)]h.
Since you can multiply in any order you want, you can move the (1/3) out front to get
V = [(1/3)]πr2h.
So, you would get 1/3 of the original volume.
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As a contrast to this, what would happen if you multiplied the radius by 1/3?
Then you would have
V = π[(1/3)r]2h
→ V = π(1/9)r2h
→ V = (1/9)πr2h
→ you would have 1/9 of the original volume.
Thank you for posting the question, and have a great evening.
Michael