how do i write this expression into standard form? (4+6i)-(-2+i)

Answer 1

Add the real parts separately from the imaginary parts:

(4 + 6i) - (-2 + i) = 4 + 6i -(-2) - i = 4 + 6i + 2 - i = 4 + 2 + 6i - i = 6 + 5i