Racquetballs have a radius of about 2.8 cm. if three balls are packaged in a can like we described for tennis balls earlier, find each volume. round to the nearest hundredth.

Question

a. the volume of one ball

b. the volume of three balls

c. the volume of the can. (remember the height is six times the radius

d. the volume of empty space in the can

e. the percentage of the can filled by the racquetballs. how does it compare to the tennis ball percentage?does this surprise you?

Answer 1

a) Volume of one ball = 4/3 × pi × r^3 = 4/3×Pi×(2.8)^3 = 92 cm^3

b) Volume of 3 balls = 3×92 = 276 cm^3

c) Volume of can = pi×r^2×h = pi×(2.8)^2×(6×2.8) = 414cm^3

d)Volume of empty space in the can = 414–276 = 138cm^3

e) Percentage of can filled by racquetballs = (276×100)/414 = 67%

I don’t have data for tennis balls to compare the percentage of space filled by tennis balls.