Time going is 840/6 = 140 sec
Time returning is 840/4 = 210 sec
Total time = 350 sec
Total distance = 1680 m
Average speed = 1680/350 = 4.8 m/sec
Anais B.
asked 02/20/19A student rides her bike from her home to the store and back again. Her average speed to the store is 6.0 m/s, and coming back home it is 4.0 m/s. If the store is 840 m away from her home, what is the average speed of the student cyclist overall in riding to the store and back?
The cyclist's average speed (the answer) is 4.8 m/s, but I don't know how to get to that answer.
Time going is 840/6 = 140 sec
Time returning is 840/4 = 210 sec
Total time = 350 sec
Total distance = 1680 m
Average speed = 1680/350 = 4.8 m/sec
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