It is easy to work backwards, but who would ever think to do so in answering this question!
f(n+1) = 1 - 1/(n+1) = (n+1-1)/(n+1) = n/(n+1)
1/f(n+1) = (n+1)/n = 1 + 1/n = f(-n)
Benson K.
asked 02/13/19If f(x) = 1- (1/x), then f(-n) is equal to...?
a) f(n)
b) 1/(f(n))
c) f(-1/n)
d) 1/(f(n+1))
d) is the correct answer, but how do you get it as the answer?
It is easy to work backwards, but who would ever think to do so in answering this question!
f(n+1) = 1 - 1/(n+1) = (n+1-1)/(n+1) = n/(n+1)
1/f(n+1) = (n+1)/n = 1 + 1/n = f(-n)
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