Well, if your answer is y=sqrt[5/(x-1)], you have a problem.
The domain of that function is x>1 and the range is (0,∞).
Try y =(x-1)^2* (sqrt(x*(5-x))/((x-2)^2)
What is the "nominator"? If you mean the numerator, it certainly does matter! Look at the answer I gave you.
The numerator defines the domain since the terms under the radical are defined only for (0,5]. The x-1 in te numerator is necessary to be sure 0 is in the range; without the x-1, the range is only the open interval (0,∞). The denominator is what gives you the unbounded range.

Paul M.
02/06/19
Fares A.
thank you02/06/19
Fares A.
I only know how to get the x under the radical to match with the given domain I have, they did not teach me about how to make it fit the range as well, I was trying to do both, is that what am I supposed to do?. A friend told me my range is the final answer, so I am getting lost here. In my exercises the numerator did not matter when I was finding the domain, unless it had the x in it, so I believe when being stricted by both the domain and the range, then both sides matters? the numerator and denominator values matters? I thought the part where x is not there was set randomly. Would you please explain how does it matter?. Also my answer should be 5-x/x-2^2? is this how to write it ?02/06/19