Lindsay J. answered 09/09/19
Tutor over multiple subjects, including Microsoft Office and GED
You need to first identify what your equation is going to be.
You know from the problem that Bert worked twice as many hours as Calvin, so you can write this as 2C
Andy worked six hours more than Bert so you could write this as 6+B.
We don't know the number of hours that Calvin worked so we will leave him as C.
Bert=2C
Calvin=C
Andy=6+B
*If you notice Andy is the only semi equation that doesn't have the same variable. We will change it to look like this: 6+2C
Now you put each part together as an equation:
2c+c+6+2c=51
Now you solve. Combine like terms
5c+6=51
-6 -6
5c= 45
divide both sides by 5
c=9
In order to find out how many hours Andy worked, you need to find out how many hours Bert works. We found out that C=9 so we know that Calvin worked 9 hours.
Bert's formula:2c We will plug in 9 in for c=2(9)=18
Bert worked 18 hours
Andy worked 6 hours more than Bert, so we add 6 to Bert's 18 hours and get=24
Calvin=9
Bert=18
Andy=24
If you add all these numbers together you get 51.