Mark M. answered 01/10/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
h(t) = -20t4 + 80t + 10
A). h(0) = 10 meters
B). h'(t) = -80t3 + 80
h'(0.5) = 70 m/hr
C). At the maximum height, h'(t) = 0
h'(t) = 0 when t = 1 hour
When 0<t<1, h'(t) > 0. So, h(t) is increasing
When t > 1, h'(t) < 0. So, h(t) is decreasing
So, maximum height when t = 1.
Maximum height = h(1) = 70 meters