Boyd was playing poker in a game with dimes, quarters, and dollar bills.

Question

Boyd was playing poker in a game with dimes, quarters, and dollar bills in the pot. He noticed there was a total of 22 coins in the pot. The number of quarters was 3 less than 4 times the number of dimes. The number of dollar bills was 8 more than the number of quarters. There were no pennies or nickels in the pot. The total pot was $29.75. How many dollar bills were there?

Answer 1

dimes=d

quarters=4d-3

bills=q+8

d+4d-3=22

5d-3=22

+3 +3

5d=25

/5 /5

d=5

q=4(5)-3

q=20-3

q=17

b=q+8

b=17+8

b=25 Here is your answer. There were 25 bills.

Let’s check our work.

29.75=.10(5)+.25(17)+1(25)

29.75=.50+4.25+25

29.75=29.75

We were correct!