Find a polynomial of least degree such that when divided by x+1 has a remainder of 2, and when divided by x-1 has a remainder of -3.

Answer 1

So f(-1) = 2 and f(1) = -3

The lowest degree polynomial is a line with slope M = (-3 -2)/(1--1) = -5/2

Using (1,-3)

B = y - mx = -3 - (-5/2)(1) = -3 - (-5/2) = (-6/2) - (-5/2) = -1/2

y = (-5/2)x - 1/2