Ishwar S. answered 12/06/18
Tutor
5
(7)
University Professor - General and Organic Chemistry
C = 5 + H
H = J + 12 --> Rearrange to solve for J --> J = H - 12
C + H + J = 80
Substitute Eq 1 and 2 into Eq 3, you get
5 + H + H + H - 12 = 80
3H - 7 = 80
3H = 87
H = 87 / 3 = 29
Substitute H = 29 into Eq 2
J = H - 12 = 29 - 12 = 17