.1x + .11(5400-x) = 550
.1x + 594 -.11x = 550
-.01x = -44
Multiply both sides by -100
x = 4400
Therefore 4400 was in the 10% account and 1000 was in the 11% account
Sydney H.
asked 11/26/18Dustin invests $5400 in two different accounts. The first account paid 10 %, the second account paid 11 % in interest. At the end of the first year he had earned $550 in interest. How much was in each account?
.1x + .11(5400-x) = 550
.1x + 594 -.11x = 550
-.01x = -44
Multiply both sides by -100
x = 4400
Therefore 4400 was in the 10% account and 1000 was in the 11% account
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