
Patrick B. answered 11/21/18
Math and computer tutor/teacher
f(5) = 0 ----> 25A + 5B + C = 0
f(38) = 0 ---> 1444A + 38B + C = 0
f(22)=15 ---> 484A + 22B + C = 15
Subtracts Equation 2 - Equation 1:
1419A + 33B = 0
Subtracts Equation 2 - Equation 3:
960A + 16B = -15
Solves by Elimination
-16 ( 1419A + 33B) = 0
33 ( 960A + 16B ) = -495
-22704A + -528B = 0
31680A + 528B = -495
8976A = -495
A = -495/8976 = -15/272
1419(-15/272) + 33B = 0
1419*(-15) + 272*33 B = 0
-21285 + 8976B = 0
B = 21285/8976 = 645/272
25 ( -15/272) + 5( 645/272) + C = 0
25 * -15 + 5 * 645 + 272C = 0
272C + 2850 = 0
C = -2850/272 = -1425/136
The quadratic function is:
f(x) = (-15/272) x^2 + (645/272) x - (1425/136)