Calculate dx/dt of the equation

Question

x = (v²sin(2theta)/(9.8)

v is a constant

Also assume that dtheta/dt is a negative constant

Answer 1

We are given x=(v^2sin(2theta))/(9.8). To find dx/dt, we will just differentiate x keeping in mind v is a constant and that dtheta/dt is a negative constant.

dx/dt=d/dt[v^2sin(2theta)/9.8]=1/(9.8)[v^2*2cos(2theta)(-dtheta/dt)+0]=1/9.8[2v^2cos(2theta)](-dtheta/dt)