In a jar there are 10 more quarters than there are dimes. The coins add up to 985 cents. How many of each coin are there?

Answer 1

Let q=quarters and d = dimes

q = d + 10

25q + 10 = 985

25(d + 10) + 10d = 985

25d + 250 + 10d = 985

35d + 250 = 985

35d = 735

d = 21

If d = 21, then q = 21 + 10 = 31

There are 21 dimes and 31 quarters.