The sum of 10 + 20 + 30 + ...+ 250 = 10(1 + 2 + 3 + ... + 25) = (1/2)* 10 * 25 * 26
need you need to add the initial 500.
In general the sum 1 + 2 + 3 + .... + n = n(n + 1)/2.
Mihai H.
asked • 11/05/18Probably a simple Mathematics formula
What would the formula for 500+10+20+30... 250 times look like?
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Mihai H.
Thank you, that's it. The challenge now was to find out "n", took me long enough to figure out how simple that would be though. In the end I managed to solve what I was trying to. Once again, thank you for you help :)11/06/18