How to solve 2-3x=2y, -3x+2=2y

Question

 I need help.

Answer 1

Valerie, I couldn't help but notice that someone "voted" Carol down on this solution she gave you.  She was right on this problem, so I'm not sure why she was so..."dissed" (?)   If you line-up the variable parts on one side and the constant values on the other side, you get the "standard form" that is taught in all schools!

 

        so;    2 -  3X =  2Y   would become     2  =   3X + 2Y     and    -3X +  2  =  2Y  would become   2 = 3X  +  2Y

 

Since these are the SAME equation, there is no point of intersection here !  When this happens, either the system has no solution  or  it contains an infinite number of solutions,  depending on the "truth" of the parts left over.  If you  "subtract "  the two equations, as Carol suggests, the  zero = zero  affect would make a true statement.  That answer results in all points being possible ( the ones that lie on that line).  Since we can't identify the total number of solutions, the infinite solution set is the answer.  If the statement was false (  i.e.  the equation might yield    5 =  -3), then no solution ( or ordered pair) will work for the problem.  That would be the "null set".  If you need further assistance, please contact us, again.  We're here to help !

 

Charles S.

Hendersonville, NC

 

Answer 2

   2-3x=2y

-(2-3x=2y)   I re-arranged the second equations so the x's would line up.

        0=0 

 

Infinite number of solutions