Andrew M. answered • 10/08/18

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Find the intersection point of the two given lines:

x + 4y = 3

x + y = 0

----------------

Subtracting will eliminate the x variable

x + 4y = 3

-(x + y = 0)

---------------

3y = 3

y = 1

Plugging into the line x+y= 0:

x + 1 = 0

x = -1

The lines cross at (-1, 1)

we want the equation of the line through (-1,1)

parallel to the line through (2,-1), (4,6)

Slope of that line is (6-(-1))/(4-2) = 7/2

Parallel lines have same slope so you want the

equation of line through (-1,1) with slope 7/2

y - y

_{1}= m(x -x_{1}) where (x_{1}, y_{1}) = (-1,1)y - 1 = (7/2)(x-(-1))

y - 1 = (7/2)(x+1)

2(y-1) = 7(x+1)

2y-2 = 7x + 7

-9 = 7x - 2y

**7x - 2y = -9**

To graph plug in a value for x and solve for y

to find a point on the graph:

2y = 7x + 9

y = (7/2)x + 9/2

y = (7/2)x + 4 1/2

x | (7/2)x + 4 1/2

-----|----------------

0 | 4 1/2

-2 | -2 1/2

There are two points on the line.

Plot and draw the line.

Paul M.

10/08/18