Every point in the xy-plane has z-coordinate equal to zero.
P = (x,y,0)
Let v be the vector from A to P and w be the vector from B to P.
v = < x-1, y-2, -3 > w = <x-7, y-6, -5>
Since v and w are orthogonal, v•w = 0
So, (x-1)(x-7) + (y-2)(y-6) + 15 = 0
x2 - 8x + 7 + y2 - 8y + 12 + 15 = 0
(x2-8x) + (y2-8y) = -34
(x2 - 8x + 16) + (y2 - 8y + 16) = -2
(x-4)2 + (y-4)2 = -2
Since the left side is never negative, there are no points, P, in the xy-plane with PA orthogonal to PB.
Bader A.
09/29/18