Raymond B. answered 03/04/21
Math, microeconomics or criminal justice
they meet at C at noon
A arrives at B, going a distance BC in 4 hours
B arrives at A, going a distance AC in 9 hours
Using A and B for the persons is a little confusing as it's also used for the locations.
But person A goes 60 mph starting at 6am sunrise, riding 10 hours, going 600 miles from A to B
Person B goes 40 mph starting at 6am sunrise riding 15 hours going 600 miles from B to A
Let t= time before noon, the time from start to meeting
Let x = person A's speed and y = person B's speed. distance = speed times time
distance AB = x(4+t) =y(9+t)
4x+9y = yt+xt
4x-9y = yt- xt add to eliminate y
8x = 2yt
4x = yt
y = 4x/t
x(4+t) = 9(4x/t) +4x= x(36/t+4)
4+t = 36/t + 4
t = 36/t
t^2 =36
t = 6 hours before noon was sunrise