
Mark M. answered 09/02/18
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
I. ax + b ≥ 0
ax + b ≥ -2
ax ≥ -b - 2
x ≥ (-b - 2) / a
II. ax + b < 0
-(ax + b) ≥ -2
ax + b ≤ 2
ax ≤ = b + 2
x ≤ (b + 2) / a
(-b - 2) / a ≤ x ≤ (b + 2) / a