Write the equation of the line parallel to y=4x-3 that passes through (0,-1)

Question

I need help pls!!

Also i didn't understand this question "Indicate the region where y≥ 4x-3 and also i need to shade. I didn't understand what should i do.

HELP PLS!

Answer 1

I will answer the question in the title.  (I suggest you post separate questions).

 

Parallel lines have the same slope, so the equation of the parallel line must be

 

y = 4x + b

 

Find b from the given point.

 

-1 = 4(0) + b

 

b = -1

 

y = 4x - 1

 

Test the answer.

Answer 2

Hi Nicole.

 

When you see the word "parallel", you know the new line will have the same slope.

 

parallel to y=4x-3

 

So, the new line will have a slope of 4

 

"Indicate the region where y≥ 4x-3

 

Plot y= 4x-3  by finding the points that make it true.  For example, (y = 0, x = 3/4), (y = 1, x = 1)  and so on.  Draw the line on your graph paper, then shade in  the portion above the line, because you want y to be greater then.

 

y = 4x + b

 

b is the y intercept ( point y when x = 0)

 

Insert new coefficients:

 

-1 = 4(0) + b

 

b = -1

 

y = 4x - 1

Answer 3

y = mx + b

 

parallel to the line with slope M=4, must also have slope M=4.

 

so y = 4x + b

 

(x=0,y=-1) is on the line

 

-1 = 4(0) + b

-1 = b

 

the equation is y = 4x + -1  or y = 4x-1

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y >=4x-3 Step 1: graph the line y=4x-3 using a SOLID line (since it is >=). [ note : if it were strictly greater than >, then you would use a dotted line] Test the origin (0,0) : 0 >= 4(0) - 3 0 > -3 Yes, it works so you shade TOWARDS the origin below the line