Philip P. answered 09/24/14
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2*sin(x)*cos(x) - cos(x) + 4*sin(x) - 2
Let's factor by grouping:
[2sin(x)cos(x) - cos(x)] + [4sin(x) - 2]
[cos(x)*(2 sin(x)-1)] + [2*(2sin(x)-1)]
Factor out the (2sin(x)-1):
(cos(x)+2)*(2sin(x)-1)