What I.

asked • 09/22/14

Differentiation

Differentiate with respect to x.
 ln[ (x+3)3 cos3x / sin x ]
 
Thank You ! :)
 
Ans : 3/(x+2) -3tan3x -cotx

1 Expert Answer

By:

SURENDRA K. answered • 09/22/14

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What I.

At the second part of the answer
[1/sin(x)*cos(3x)*((x+3)^3)]*[3sin(x)*cos(3x)*((x+3)^2)-3sin(x)*sin(3x)*((x+3)^3)-cos(x)*cos(3x)*(x+3)^3]
how did the sinx came about?
 
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09/23/14

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