Gas Laws Math

Question

A pressure cooker is used to heat up food quickly. If the air in a pressure cooker is initially at 450K under a pressure of 100kPa, what will the pressure be when the temperature is increased to 600K?

Answer 1

Since the volume of the pressure cooker is constant, you have the relationship that P₁/T₁ = P₂/T₂.

P₁ = 100 kPa

T₁ = 450K

P₂ = ?

T₂ = 600K

 

100/450 = P₂/600

P₂ = 133 kPa (to 3 significant figures)

This is an example of Gay-Lussac's law