at time = 20 s a rocket velocity is 15,000m/s, up, at time = 40 s the rocket's velocity was 17,500 m/s, up. what was its acceleration during that time?

Question

at time = 20 s a rocket velocity is 15,000m/s, up, at time = 40 s the rocket's velocity was 17,500 m/s, up. what was its acceleration during that time? please help

Answer 1

To find acceleration we use the formula a=(V_f-V_i)/T where a is acceleration V_f is the final velocity V_i is the initial velocity and T is time. Since we start at 20 seconds and end at 40 seconds, the time elapsed is 40-20=20 seconds. Our initial velocity is 15,000 m/s and our final velocity is 17,500 m/s. Plugging these values  into our equation, we get a=(17,500 m/s-15,000 m/s)/20 s.

 

Our next step  is to solve the subtraction in the parentheses:

 

a=(2,500 m/s) /20s

 

Next we divide:

 

a=125m/s²

 

Notice that since the velocities were already expressed in terms of m/s, and we have to divide by the time, which is expressed in seconds, our final answer is expressed in terms of m/s².

Answer 2

Answer 3

acceleration = change of velocity / change of time

So, a = (17,500 - 15,000)/20 = 125 m/s^2 <==Answer {edit}