Philip P. answered • 06/25/18

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**3**

^{x}= 2^{x-1}log(3

^{x}) = log(2^{x-1})x log(3) = (x-1)log(2) [log property: log(a

^{b}) = b log(a)]x log(3) = x log(2) - log(2)

x log(3) - x log(2)) = -log(2)

x (log(3) - log(2)) = -log(2)

**x = -log(2)/(log(3)-log(2)) = log(2)/log(2/3)**[log property: log(a) - log(b) = log(a/b)]

Use you calculator if you want a numerical answer. You can use any base log.