
Bobosharif S. answered 06/02/18
Tutor
4.4
(32)
PhD in Math, MS's in Calulus
(x9+512)=(x+2)(x8-2x7+4x6-8x5+16x4-32x3+64x2-128x+256)
So
1-2+4-8+16-32+64-128+256≠0
a8 + a7 + ... + a1 + a0 ≠0