2ax+6xc+ba+3bc

Question

How do we solve this problem?

Answer 1

It looks like the first two terms have a common factor of 2x, and the second two have a common factor of b. 

2x (a + 3c) + b (a + 3c)

We can now pull out the (a + 3c) as a common factor to get

(a + 3c) (2x + b)