Jeffrey K. answered • 09/21/20

Together, we build an iron base in mathematics and physics

Gnarls, here's how to tackle this one.

(a) The relevant equation of motion is: v^{2} = v_{0}^{2} + 2as

We know a, the acceleration of gravity, and s, the distance the meteorite travels.

However, we aren't given the meteor's initial speed, v_{0}.

Therefore, this problem can't be done with the given information!

BTW Meteors enter the earth's atmosphere at high speeds, ranging from 11 km/sec to 72 km/sec (25,000 to 160,000 mph).

b) No, we are given v_{0 }=_{ }1,800 m/s. Applying the equation in part a):

v^{2} = 1800^{2} + 2 x 9.8 x 7.1 x 10^{6}

Therefore, KE = 1/2 mv^{2 }= 0.5 ( 1800^{2} + 2 x 9.8 x 7.1 x 10^{6})

I leave the calculation for you, as an exrecise!

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