I need the solutions over the interval [0 degrees, 360 degrees) 9 sin^2 θ tanθ-9 sin^2 θ=0

Question

I need the solution set

Answer 1

9sin²(θ) tan(θ)-9sin²(θ)=0

9sin²(θ)(tan(θ)-1)=0

From here it follows that 

a)sin(θ)=0  

b) tanθ=1

 

a) θ=180º and θ=360º

b) θ=45º  and θ=225º