Algebra 2 practice

Question

Find the value of q in the following system so that the solution to the system is {(x,y) : x - 3 = 4}
x - 3y = 4
2x - 6y = Q

 

Please Help I do not understand.

Answer 1

x - 3y = 4
2x - 6y = Q

 

you use the elimination method. To start, multiply the first equation by 2 

 

2x - 6y = 8
2x - 6y = Q

 

Because the left side of both equations is the same, the right side of both equations must also be the same.

 

Therefore Q = 8

 

Because the equations are identical, we really have only one equation so there are an infinite numbers of solutions (x,y).

 

I'm not sure what the bit about x - 3 = 4 means.???????

Answer 2

OK, I will believe you that this is not a quiz.

 

What is the value of x if x - 3 = 4?

 

Since you have a value of x, substitute it in the first equation to find the value of y, then use both values in the third equation to find the value of q.