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A boy's coins, consisting of nickels and dimes, amount to $2.15. If the # of dimes exceeds 3 times the # of nickels by 4, find the # of each coin

I don't understand the wording of the question, and how I'm suppose to make the equation

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Andy C. | Math/Physics TutorMath/Physics Tutor
4.9 4.9 (19 lesson ratings) (19)
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10D + 5N = 215
 
D = 3N+4
 
10(3n+4) + 5n = 215
 
30n + 40 + 5n = 215
 
35n + 40 = 215
 
35n = 175
 
n = 5
 
5 nickles
19 dimes
 
$1.90 + 0.25 = 2.15