A boy's coins, consisting of nickels and dimes, amount to $2.15. If the # of dimes exceeds 3 times the # of nickels by 4, find the # of each coin

Question

I don't understand the wording of the question, and how I'm suppose to make the equation

Answer 1

10D + 5N = 215

 

D = 3N+4

 

10(3n+4) + 5n = 215

 

30n + 40 + 5n = 215

 

35n + 40 = 215

 

35n = 175

 

n = 5

 

5 nickles

19 dimes

 

$1.90 + 0.25 = 2.15