Melvin H. answered 09/16/14
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The vertex form for the equation of a parabola is y =a(x - h)2 + k where the point (h,k) is the vertex of the parabola.; i.e. the lowest point (or highest point) located a x = h and y = k.
Doing a little algebra one can shift the equation around to (x - h)2 = ( y - k)/a (Note: A word of caution here. The right hand side of the equation could be negative if you pick a value of y that is outside of its range. Don't worry about this just yet, we well address it later.)
Now, take the square root of both sides ( x - h) = ± √[(y - k)/a] (Note: Every item on the rhs is under the √.)
and solve for h: h = x ± √[(y - k)/a] This is the best, and correct, solution for h. (But be careful.)
Comment: The original equation was y = a(x -h)2 + k . Depending on the sign of coefficient a, the parabola either opens upwards a›0, or downwards, a<0. The trivial case of a = 0 is just a horizontal line, which has no vertex. The original equation has a domain of all real numbers. Its range is more limited, determined by the values of a and k. One must take care before blindly plugging values for y into our solution for h. These values must match the original equation; basically (y - k)/a must be ≥ 0.
Comment: When one takes the square root of an equation one runs the risk of introducing extraneous or "mirror-image" solutions. By convention we usually choose the +√ of ±√ . This usually works the best.