Find three consecutive integers such that five times the third integer equals twice the first integer plus seven more than the second integer.

Question

Defining the vatiables before starting tends to make the problem easier.

Answer 1

The three integers are x, x+1, x+2

 

5(x+2) = 2x + ((x+1)+7)     "five times the third equals twice the first plus seven more than the second"

 

This is one equation with one unknown, so you should be able to solve for x.